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ViewModelProvider.of 过时方法解决
2022-07-07 02:14:00 【梦想改变生活】
过时方法
open fun <T : ViewModel?> createViewModel(activity: FragmentActivity?, cls: Class<T>?): T {
return ViewModelProviders.of(activity!!).get(cls)
}
替换成
open fun <T : ViewModel?> createViewModel(activity: FragmentActivity?, cls: Class<T>?): T {
return ViewModelProvider(activity!!).get(cls!!)
}
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