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每日一题——PAT乙级1002题
2022-07-07 21:49:00 【InfoQ】
一、PAT (Basic Level) Practice (中文)第1002题
输入格式:
输出格式:
输入样例:
1234567890987654321123456789
输出样例:
yi san wu
transform={'1':'yi','2':'er','3':'san','4':'si','5':'wu','6':'liu','7':'qi','8':'ba','9':'jiu','0':'ling'}
#输入
a=input()
#将输入的数字字符串转换为列表的形式
b=list(a)
#将数字中的每一位求和
c=sum(int(i) for i in b)
#求和结果转为字符串形式,用于计算长度
d=str(c)
#标记位,用来判断for循环的最后一个
flag=0
for j in d:
flag=flag+1
#如果为for循环的最后一位,则不输出空格
if flag==len(d):
#print默认的end为end='\n',先根据情况将其修改
print(transform[j],end='')
else:
print(transform[j],end=' ')
transform={'1':'yi','2':'er','3':'san','4':'si','5':'wu','6':'liu','7':'qi','8':'ba','9':'jiu','0':'ling'}
a=input()
print("input输入的类型:",type(a))
b=list(a)
print("转发化为列表的b为:",b)
#c=sum(int(i) for i in b)
sum=0
for i in a:
s=int(i)
sum=sum+s
print('sum的数据类型:',type(sum)," 结果: ",sum)
d=str(sum)
print("转化为字符串形式的sum"," 类型:",type(d)," 字符串形式的数:",d," 他的长度:",len(d))
flag=0
for j in d:
flag=flag+1
if flag==len(d):
print(transform[j],end='')
else:
print(transform[j],end=' ')
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