当前位置:网站首页>Hypothesis testing -- learning notes of Chapter 8 of probability theory and mathematical statistics
Hypothesis testing -- learning notes of Chapter 8 of probability theory and mathematical statistics
2022-07-05 04:23:00 【IOT classmate Huang】
Hypothesis testing ——《 Probability theory and mathematical statistics 》 Chapter VIII study notes
List of articles
Preface
Thanks to typhoon siemba , Let me not go back to the dormitory , Forced to spend the night in the Laboratory , reasoning , Cannot sleep! , Just as the final exam is approaching , Decided to write a study note of Chapter 8 .
Just like the previous series , Teaching materials remain unchanged . Content , Select the first three sections of Chapter 8 , Hypothesis testing , Normal mean , Knowledge points of three parts of normal variance , Why is there nothing else , Because I probably won't take this exam .
Formally , Compared with the previous chapters, many textbook definitions are written , This time I will have more personal understanding , Try to hit the test site directly .
MindMap
Hypothesis testing
This section actually tells you some definitions of hypothesis testing , And the process and steps of solving the problem of hypothesis testing .
Some definitions
Significance level
The standard we use to measure the inspection , Generally, in the formula α
appear .
Test statistic
Z = X ‾ − μ 0 σ / n Z = \frac{\overline{X} - \mu_0}{\sigma/\sqrt n} Z=σ/nX−μ0
The null hypothesis And The alternative hypothesis
We describe the inspection problem as : At the level of significance α Next , Test the hypothesis :
H 0 : μ = μ 0 , H 1 : μ ≠ μ 0 H_0:\mu =\mu_0, \qquad H_1 : \mu \neq \mu_0 H0:μ=μ0,H1:μ=μ0
H0 by The null hypothesis
, H1 by The alternative hypothesis
.
Reject domain
Is to take a value in a certain area as When testing the value of Statistics , Refuse The null hypothesis , Or accept the alternative hypothesis , This region is the rejection domain , The boundary point of the rejection domain is actually called critical point
.
Significance test
Because the test is based on samples , So the test is bound to make mistakes , There are two main mistakes :
- H0 It's true , But refuse .
- H1 It's true , But accept the original hypothesis .
We obviously hope that the probability of making these two kinds of mistakes is small , But in mathematical statistics , If the sample size is limited , While reducing the probability of making a kind of mistake , The probability of the other kind tends to increase . So in mathematical statistics , The first kind of control is adopted , Don't consider
The second category . This test is Hypothesis testing .
Bilateral inspection and unilateral inspection
This is actually when we are making assumptions , about H1,μ May be greater than μ0, It may be less than μ0, If it is both possible , That's it Bilateral assumptions
, And if it's just one possibility , That's it Unilateral assumptions
, According to the direction, it can be divided into Check on the left and Check on the right . For direction , My personal understanding is to see Reject the domain or choose the assumed direction .
Problem solving steps for personal understanding
Through reading and understanding textbook examples , Found the solution process of hypothesis testing problem :
- First, determine the test hypothesis according to the topic .
- Determine the test statistics according to the parameters .
- Then judge the hypothesis according to the hypothesis and test statistics , Then determine the reject domain .
- sampling , In fact, it is to judge whether to accept the original hypothesis according to the observed value of the sample .
All the populations in this article are normal populations , For its two parameters , mean value μ And variance σ^2, There are two hypothesis tests .
Hypothesis test of normal population mean
Single population
Here, according to whether the variance is known , Can be divided into Z test
and t test
.
The variance is known ,Z test
It's very simple , According to the hypothesis, we need to test whether the sample mean meets the hypothesis , At the level of significance α And other parameters , The test statistic is :
Z = X ‾ − μ 0 σ / n Z ∼ N ( μ , σ 2 ) Z = \frac{\overline{X} - \mu_0}{\sigma/\sqrt n} \\ Z \sim N(\mu, \sigma^2) Z=σ/nX−μ0Z∼N(μ,σ2)
Next, we only need to solve it according to whether it is unilateral hypothesis or bilateral hypothesis .
Take two sides α/2, The absolute value of the test statistic is higher than Corresponding to the significance level The normal function value rejects the original assumption .
The variance is unknown ,t test
This is actually Sample variance is used s
To approximate replacement Total variance σ, Of course, we need to use t Distribution .
X ‾ − μ 0 S / n ∼ t ( n − 1 ) \frac{\overline{X} - \mu_0}{S/\sqrt n} \sim t(n-1) S/nX−μ0∼t(n−1)
Two overall ——t test
For two independent normal populations
N ( μ 1 , σ 2 ) , N ( μ 2 , σ 2 ) N(\mu_1, \sigma^2), N(\mu_2, \sigma^2) N(μ1,σ2),N(μ2,σ2)
The variance is the same , The mean is different , So we can eliminate the test hypothesis :
H 0 : μ 1 − μ 2 = δ , H 1 : μ 1 − μ 2 ≠ δ H_0: \mu_1 - \mu_2 = \delta, \quad H_1:\mu_1 - \mu_2 \neq \delta H0:μ1−μ2=δ,H1:μ1−μ2=δ
So give the test statistics :
t = ( X ‾ − Y ‾ ) − δ S w 1 n 1 + 1 n 2 S w 2 = ( n 1 − 1 ) S 1 2 + ( n 2 − 1 ) S 2 2 n 1 n 2 − 2 t= \frac{(\overline{X} - \overline{Y})- \delta}{S_w\sqrt{\frac1{n_1} + \frac 1{n_2}}} \\ S_w^2 = \frac{(n_1 - 1)S_1^2 + (n_2 - 1)S^2_2}{n_1 n_2 - 2} t=Swn11+n21(X−Y)−δSw2=n1n2−2(n1−1)S12+(n2−1)S22
Test of paired data ——t test
In fact, here is to compare the two groups of data to find the difference , Then do the test , We usually subtract the data directly as a new normal population sample , The next step is actually a single overall situation .
Hypothesis test of normal population variance
Single population
In the mean , So here's what we're going to use Z and t test , To put it bluntly, it means using Normal distribution
and t Distribution
, But in the hypothesis test of variance , In fact, it uses
( n − 1 ) S 2 σ 0 2 ∼ χ 2 ( n − 1 ) \frac{(n-1)S^2}{\sigma_0^2} \sim \chi^2(n - 1) σ02(n−1)S2∼χ2(n−1)
Two overall
What is used is F Distribution
S 1 2 / S 2 2 σ 1 2 / σ 2 2 ∼ F ( n 1 − 1 , n 2 − 1 ) \frac{S_1^2/ S_2^2}{\sigma_1^2/ \sigma_2^2} \sim F(n_1-1, n_2 -1) σ12/σ22S12/S22∼F(n1−1,n2−1)
Test method table of normal population
The latter
It's dawn , Go back to bed , This chapter will be better read in combination with the textbook .
边栏推荐
- Moco is not suitable for target detection? MsrA proposes object level comparative learning target detection pre training method SOCO! Performance SOTA! (NeurIPS 2021)...
- Ctfshow web entry code audit
- Online text line fixed length fill tool
- 官宣!第三届云原生编程挑战赛正式启动!
- Judge whether the stack order is reasonable according to the stack order
- The development of mobile IM based on TCP still needs to keep the heartbeat alive
- 函数(易错)
- How to solve the problem that easycvr changes the recording storage path and does not generate recording files?
- A应用唤醒B应该快速方法
- Learning notes 8
猜你喜欢
C26451: arithmetic overflow: use the operator * on a 4-byte value, and then convert the result to an 8-byte value. To avoid overflow, cast the value to wide type before calling the operator * (io.2)
Sequence diagram of single sign on Certification Center
The development of mobile IM based on TCP still needs to keep the heartbeat alive
[moteur illusoire UE] il ne faut que six étapes pour réaliser le déploiement du flux de pixels ue5 et éviter les détours! (4.26 et 4.27 principes similaires)
如何实现实时音视频聊天功能
小程序中实现文章的关注功能
指针函数(基础)
[illusory engine UE] method to realize close-range rotation of operating objects under fuzzy background and pit recording
Sword finger offer 04 Search in two-dimensional array
About the prompt loading after appscan is opened: guilogic, it keeps loading and gets stuck. My personal solution. (it may be the first solution available in the whole network at present)
随机推荐
C language course setting: cinema ticket selling management system
解密函数计算异步任务能力之「任务的状态及生命周期管理」
Number of possible stack order types of stack order with length n
Fonction (sujette aux erreurs)
【虚幻引擎UE】实现测绘三脚架展开动画制作
How to solve the problem that easycvr changes the recording storage path and does not generate recording files?
Three level linkage demo of uniapp uview u-picker components
mysql的七种join连接查询
Sword finger offer 04 Search in two-dimensional array
Technical tutorial: how to use easydss to push live streaming to qiniu cloud?
Hexadecimal to octal
首席信息官如何利用业务分析构建业务价值?
【thingsboard】替换首页logo的方法
Ctfshow 2022 Spring Festival welcome (detailed commentary)
Threejs Internet of things, 3D visualization of farms (II)
Threejs Internet of things, 3D visualization of farms (I)
Rome链分析
Burpsuite grabs app packets
假设检验——《概率论与数理统计》第八章学习笔记
北京程序员的真实一天!!!!!