Double to int precision loss

Let's first look at the phenomenon of precision loss ：

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
    
   double a = 74.46;
   int b = a * 100;

   cout << "a: " << a << " b: " << b <<endl;
   return 0;
}

result ：

solve ： Use rounding method

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
    
   double a = 74.46;
   int b = round(a * 100);

   cout << "a: " << a << " b: " << b << endl;
   return 0;
}

result ：