当前位置:网站首页>浙大版《C语言程序设计实验与习题指导(第3版)》题目集
浙大版《C语言程序设计实验与习题指导(第3版)》题目集
2022-07-06 09:23:00 【无二三事】
实验5-7 使用函数求1到10的阶乘和
分数 10
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作者 张高燕
单位 浙大城市学院
本题要求实现一个计算非负整数阶乘的简单函数,使得可以利用该函数,计算1!+2!+⋯+10!的值。
函数接口定义:
double fact( int n );
其中n
是用户传入的参数,其值不超过10。如果n
是非负整数,则该函数必须返回n
的阶乘。
裁判测试程序样例:
#include <stdio.h> double fact( int n ); int main(void) { int i; double sum; sum = 0; for(i = 1; i <= 10; i++) sum = sum + fact(i); printf("1!+2!+...+10! = %f\n", sum); return 0; } /* 你的代码将被嵌在这里 */
输入样例:
本题没有输入。
输出样例:
1!+2!+...+10! = 4037913.000000
代码长度限制
16 KB
时间限制
400 ms
内存限制
64 MB
代码具体实现:
double fact( int n ){
int i = 1;
for(int j=1;j<=n;j++){
i *= j;
}
return i;
}
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